Base operand of arrow has non-pointer type ‘Foo’

From Cppsyntax

You can get the error

 base operand of ‘->’ has non-pointer type ‘Foo’

if you try to use a "->" where you should be using a ".".

It is a little bit difficult to make this happen, since new Foo() returns a pointer to Foo, but you can get in this situation with references.

WRONG

 class Foo 
 {
   int i;
   public: int getI()
   {
     return i;
   }
 };
 class Blort
 {   
   int one(Foo &aFoo)
   {
     aFoo->getI();       // aFoo is a non-pointer type here
   }
 };

RIGHT

 class Foo 
 {
   int i;
   public: int getI()
   {
     return i;
   }
 };
 class Blort
 {   
   int one(Foo &aFoo)
   {
     aFoo.getI();       // use a "." instead of a "->"
   }
 };